Answer by Teh Rod for Integrate the indefinite integral?
Rationalizing yields $\int\frac{x\left(\sqrt{x^2+a^2}-\sqrt{x^2-a^2}\right)}{2a^2}$ using your substitution the integral becomes...
View ArticleAnswer by mickep for Integrate the indefinite integral?
For example,$$\int(t-a^2)^{1/2}\,dt=\frac{2}{3}(t-a^2)^{3/2}+C$$
View ArticleIntegrate the indefinite integral?
Integrate the indefinite integral ?$$\int \frac{x}{\sqrt{x^2-a^2} + \sqrt{x^2+a^2}}dx$$My try :-Let $x^2 = t \to 2xdx=dt$ and then rationalizeI have,$$\frac{1}{4a^2}\int \sqrt{t-a^2}- \sqrt{t+a^2}dt$$I...
View Article
More Pages to Explore .....
